Butanol Answers
Butanol or ethanol has the higher octane number?
Q. I'm quite confusing because in some reports, butanol has the higher octane rating number, but in the others, they showed the reverse information. Which one is reliable?
Asked by HeART - Wed Dec 24 23:58:21 2008 - Biology - 1 Answers - Comments
A. You're probably confused by the difference between energy contained in the hydrocarbon and its octane number. Octane numbers go up as energy decreases, so ethanol, which has the higher octane number (129), actually contains less energy that butanol (anywhere in the 90s depending on formulation). Remember it this way. E10 gasoline, which is what you probably normally buy, has an octane rating of about 88. However, if you've ever bought E85 ethanol, you'll know that your car burns through it a lot faster. That's because it has a lot less energy in it, meaning its octane number is much higher. Butanol is much closer to E10, but it's not as commercially viable to produce as ethanol. The actual energy content in MJ/L is: E10: 33.7 Methanol: 17.9 [cont.]
Answered by Alex - Thu Dec 25 00:12:43 2008
Q. I'm quite confusing because in some reports, butanol has the higher octane rating number, but in the others, they showed the reverse information. Which one is reliable?
Asked by HeART - Wed Dec 24 23:58:21 2008 - Biology - 1 Answers - Comments
A. You're probably confused by the difference between energy contained in the hydrocarbon and its octane number. Octane numbers go up as energy decreases, so ethanol, which has the higher octane number (129), actually contains less energy that butanol (anywhere in the 90s depending on formulation). Remember it this way. E10 gasoline, which is what you probably normally buy, has an octane rating of about 88. However, if you've ever bought E85 ethanol, you'll know that your car burns through it a lot faster. That's because it has a lot less energy in it, meaning its octane number is much higher. Butanol is much closer to E10, but it's not as commercially viable to produce as ethanol. The actual energy content in MJ/L is: E10: 33.7 Methanol: 17.9 [cont.]
Answered by Alex - Thu Dec 25 00:12:43 2008
How do I calculate the number of moles of butanol used in a reaction ?
Q. I also have to calculate the number of moles of the reagents Na Br and Sulfuric Acid 1-Butanol -> (Reagents Na Br, Heat/conc. H2SO4) CH3CH2CH2CH2Br + Na HSO4 +H2O
Asked by Ali M - Wed Oct 20 23:07:55 2010 - Mathematics - 3 Answers - Comments
A. You'll need to have a grams to find moles or use the equation Pv=n RT given pressure, temperature, volume.. I'm missing some information in order to help.
Answered by xxtrinidadhunnixx - Wed Oct 20 23:09:31 2010
Q. I also have to calculate the number of moles of the reagents Na Br and Sulfuric Acid 1-Butanol -> (Reagents Na Br, Heat/conc. H2SO4) CH3CH2CH2CH2Br + Na HSO4 +H2O
Asked by Ali M - Wed Oct 20 23:07:55 2010 - Mathematics - 3 Answers - Comments
A. You'll need to have a grams to find moles or use the equation Pv=n RT given pressure, temperature, volume.. I'm missing some information in order to help.
Answered by xxtrinidadhunnixx - Wed Oct 20 23:09:31 2010
How do you calculate the mol% of 1-butanol in a mixture of 3.7 g of 1-butanol and 5.2 g of ethanol?
Q. How do you calculate the mol% of 1-butanol in a mixture of 3.7 g of 1-butanol and 5.2 g of ethanol? Thanks sooo much!
Asked by Eric J - Tue Jun 24 21:44:06 2008 - Chemistry - 3 Answers - Comments
A. 1-Butanol C4H9OH mol.mass = 48 + 10 + 16 = 74g/mol. 3.7g / 74g/mol = 0.05mol. Ethanol C2H5OH mol.mass = 24 + 6 + 16 = 46g/mol. 5.2g / 46g/mol. = 0.113mol. Total mol. = 0.05 + 0.113 = 0.163mol. 0.05 / 0.163 = 0.3067 x 100% = 30.67% 1-butanol.
Answered by Norrie - Tue Jun 24 22:11:06 2008
Q. How do you calculate the mol% of 1-butanol in a mixture of 3.7 g of 1-butanol and 5.2 g of ethanol? Thanks sooo much!
Asked by Eric J - Tue Jun 24 21:44:06 2008 - Chemistry - 3 Answers - Comments
A. 1-Butanol C4H9OH mol.mass = 48 + 10 + 16 = 74g/mol. 3.7g / 74g/mol = 0.05mol. Ethanol C2H5OH mol.mass = 24 + 6 + 16 = 46g/mol. 5.2g / 46g/mol. = 0.113mol. Total mol. = 0.05 + 0.113 = 0.163mol. 0.05 / 0.163 = 0.3067 x 100% = 30.67% 1-butanol.
Answered by Norrie - Tue Jun 24 22:11:06 2008
What is the molarity of 1-butanol?
Q. I have to figure out how many moles I started with to help me figure out a percent yield problem. I started with 10 m L of 1-butanol. How do I figure out how many moles I started with? I guessed I would use the molarity, but I can't find it.
Asked by greensock - Thu Oct 11 18:52:47 2007 - Chemistry - 1 Answers - Comments
A. If you have 10 m L of pure 1-butanol, then you must use it's density to find out the number of grams then use this to find out the number of moles. If it's pure, then there's no solution, it's just 1-butanol so molarity has no meaning.
Answered by Science Geek - Thu Oct 11 19:04:55 2007
Q. I have to figure out how many moles I started with to help me figure out a percent yield problem. I started with 10 m L of 1-butanol. How do I figure out how many moles I started with? I guessed I would use the molarity, but I can't find it.
Asked by greensock - Thu Oct 11 18:52:47 2007 - Chemistry - 1 Answers - Comments
A. If you have 10 m L of pure 1-butanol, then you must use it's density to find out the number of grams then use this to find out the number of moles. If it's pure, then there's no solution, it's just 1-butanol so molarity has no meaning.
Answered by Science Geek - Thu Oct 11 19:04:55 2007
What is the difference between butanol and n-butyl alcohol and is it sold in different concentrations?
Q. Im doing a chemistry lab where testing the viscosity of alcohols, I used a alcohol from a bottle that said "n-Butyl alcohol"
Asked by the firefox - Sun Mar 14 22:36:26 2010 - Chemistry - 1 Answers - Comments
A. well, you can have different isomers of butanol. Butane is 4 carbons, so you can have the -OH on the first or the second carbon (the third and the fourth would be the same as the first or second, just from the other side). YOu could also have iso-butanol (ignore the periods - they're just so spacing formats it correctly. ...c c-c-c ...o ...h anyway n-butanol is the same as 1-butanol. If it was just labeled as butanol, odds are pretty good that it's 1-butanol C-C-C-C-OH
Answered by Jordan - Sun Mar 14 22:41:33 2010
Q. Im doing a chemistry lab where testing the viscosity of alcohols, I used a alcohol from a bottle that said "n-Butyl alcohol"
Asked by the firefox - Sun Mar 14 22:36:26 2010 - Chemistry - 1 Answers - Comments
A. well, you can have different isomers of butanol. Butane is 4 carbons, so you can have the -OH on the first or the second carbon (the third and the fourth would be the same as the first or second, just from the other side). YOu could also have iso-butanol (ignore the periods - they're just so spacing formats it correctly. ...c c-c-c ...o ...h anyway n-butanol is the same as 1-butanol. If it was just labeled as butanol, odds are pretty good that it's 1-butanol C-C-C-C-OH
Answered by Jordan - Sun Mar 14 22:41:33 2010
How does one draw chemical structures for alcohols like 2-butanol?
Q. And how do you determine whether they are primary, secondary, or tertiary? Whats the difference? and how do you do it for really long ones like 3,3 dimethyl-2-butanol. I understand the butanol now, but i dont understand the 3,3 dimethyl.
Asked by Tears Don't Fall <3 - Thu Nov 8 17:32:22 2007 - Chemistry - 4 Answers - Comments
A. The 2 indicates what carbon the alcohol group is attached to. Primary, secondary, and tertiary refer to how the carbon is bonded to other carbons. A primary carbon is bonded to one other carbon, secondary 2 other carbons, tertiary 3 other carbons, and quaternary 4 carbons. In 2-butanol, the OH group is attached to a secondary carbon. The second part is simple too. 3,3-dimethyl means that you have two methyl groups, CH3, attached to the third carbon atom. Lets say you have 1,3,5-trimethyl-2-pentanol. That means that you have three methyl groups, and a hydroxy (alcohol) group attached to a pentane molecule. To place the substiuents, just read the numbers in front, those tell you which carbon to place it on. So you would have a methyl group… [cont.]
Answered by mcalhoun333 - Thu Nov 8 17:41:26 2007
Q. And how do you determine whether they are primary, secondary, or tertiary? Whats the difference? and how do you do it for really long ones like 3,3 dimethyl-2-butanol. I understand the butanol now, but i dont understand the 3,3 dimethyl.
Asked by Tears Don't Fall <3 - Thu Nov 8 17:32:22 2007 - Chemistry - 4 Answers - Comments
A. The 2 indicates what carbon the alcohol group is attached to. Primary, secondary, and tertiary refer to how the carbon is bonded to other carbons. A primary carbon is bonded to one other carbon, secondary 2 other carbons, tertiary 3 other carbons, and quaternary 4 carbons. In 2-butanol, the OH group is attached to a secondary carbon. The second part is simple too. 3,3-dimethyl means that you have two methyl groups, CH3, attached to the third carbon atom. Lets say you have 1,3,5-trimethyl-2-pentanol. That means that you have three methyl groups, and a hydroxy (alcohol) group attached to a pentane molecule. To place the substiuents, just read the numbers in front, those tell you which carbon to place it on. So you would have a methyl group… [cont.]
Answered by mcalhoun333 - Thu Nov 8 17:41:26 2007
how to separate hexanol , butanol and water in the same column . Chemical Enginering?
Q. I have separated hexanol , butanol and water in the same column and I got 99% purity of hexanol on the bottom stream of column and butanol and water are on the top of distillation. My instructor said that is impossible. Is there the way to separate it? Thanks Column is 22 stages and the feed at stage 17. He said the azeotrope of butanol/ water and hexanol/water are slightly the same which is hard to separate.
Asked by jennifer - Mon Dec 6 18:50:51 2010 - Engineering - 2 Answers - Comments
A. I'm not sure what your instructor means that your distillation is "impossible." Let's look at what you've got. Water has a boiling point of 100 C, butanol is 118 C, and hexanol is 157 C. This would imply an easy separation. But, water forms an azeotrope with butanol at 93 C and with hexanol at 98 C. The water/butanol azeotrope is a 45%/55% mixture. So, if you have roughly equal parts water and butanol, and you hold the distillation temp to 93 C, almost all of the water and butanol will be removed in the overhead stream. You will likely recover some water and hexanol in the overhead stream, but it will be much less because this azeotrope doesn't begin to boil until 98 C. Once all the water is gone, heating to 118 C will remove any… [cont.]
Answered by Typcynic - Mon Dec 6 20:56:29 2010
Q. I have separated hexanol , butanol and water in the same column and I got 99% purity of hexanol on the bottom stream of column and butanol and water are on the top of distillation. My instructor said that is impossible. Is there the way to separate it? Thanks Column is 22 stages and the feed at stage 17. He said the azeotrope of butanol/ water and hexanol/water are slightly the same which is hard to separate.
Asked by jennifer - Mon Dec 6 18:50:51 2010 - Engineering - 2 Answers - Comments
A. I'm not sure what your instructor means that your distillation is "impossible." Let's look at what you've got. Water has a boiling point of 100 C, butanol is 118 C, and hexanol is 157 C. This would imply an easy separation. But, water forms an azeotrope with butanol at 93 C and with hexanol at 98 C. The water/butanol azeotrope is a 45%/55% mixture. So, if you have roughly equal parts water and butanol, and you hold the distillation temp to 93 C, almost all of the water and butanol will be removed in the overhead stream. You will likely recover some water and hexanol in the overhead stream, but it will be much less because this azeotrope doesn't begin to boil until 98 C. Once all the water is gone, heating to 118 C will remove any… [cont.]
Answered by Typcynic - Mon Dec 6 20:56:29 2010
What happens when an isomer of butanol reacts with a) hydrochloric acid b) potassium permanganate solution ?
Q. I'm having some problems with chemistry homework... When 1- and 2- butanol react with HCl(aq), does the solution become cloudy or clear? And does this change when 2-methyl-2-propanol reacts with HCl(aq)??? Also when they react with potassium permanganate, should there be a change of colour. Any valid answers to any of my questions are GREATLY appreciated. Thank you.
Asked by Elle*Cookie - Sun Sep 27 16:57:00 2009 - Chemistry - 1 Answers - Comments
A. This is based on Lucas Test Alcohols are soluble in Lucas Reagent (HCl) while alkyl halides are not and produce turbidity. This test is used to differentiate between various alcohols : A tertiary alcohol forms halide easily and produces turbidity immediately. A secondary alcohol produces turbidity gradually as halide is formed with a little difficulty. A primary halide does not form halide at room temperature and thus does not produce turbidity. So 2 - methyl-2-propanol (tertiary) and 2-butanol will produce turbidity. 1-butanol will not. Hope this helps. your_
Answered by Prashant - Mon Sep 28 13:17:56 2009
Q. I'm having some problems with chemistry homework... When 1- and 2- butanol react with HCl(aq), does the solution become cloudy or clear? And does this change when 2-methyl-2-propanol reacts with HCl(aq)??? Also when they react with potassium permanganate, should there be a change of colour. Any valid answers to any of my questions are GREATLY appreciated. Thank you.
Asked by Elle*Cookie - Sun Sep 27 16:57:00 2009 - Chemistry - 1 Answers - Comments
A. This is based on Lucas Test Alcohols are soluble in Lucas Reagent (HCl) while alkyl halides are not and produce turbidity. This test is used to differentiate between various alcohols : A tertiary alcohol forms halide easily and produces turbidity immediately. A secondary alcohol produces turbidity gradually as halide is formed with a little difficulty. A primary halide does not form halide at room temperature and thus does not produce turbidity. So 2 - methyl-2-propanol (tertiary) and 2-butanol will produce turbidity. 1-butanol will not. Hope this helps. your_
Answered by Prashant - Mon Sep 28 13:17:56 2009
What is the mechanism of the reaction when 2-methyl-2-butanol is heated with concentrated sulfuric acid?
Q. I'm having a hard time with this one, anyone care to explain? Tertiary alcohols undergo either substitution or dehydration depending on the reaction conditions. What is the mechanism of the reaction when 2-methyl-2-butanol is heated with concentrated sulfuric acid? Thanks!
Asked by Chance - Mon Oct 20 19:00:58 2008 - Chemistry - 1 Answers - 2 Comments
A. 2-methyl-2-butene. This will undergo an E1 reaction (elimination under acidic conditions) or for your sake, dehydration. The hydroxy oxygen will be protonated which results in a positive charge and thus forming a good leaving group. Then the cation dissociates, resulting a tertiary carbocation and water (this particular carbocation is the driving force of the reaction since it is stable and there's no positive charge on oxygen since oxygen is electronegative). Then the water molecule deprotonates the carbocation by taking a hydrogen from the beta carbon (the carbon adjacent to the positively charged carbon) resulting in 2-methylbutene.
Answered by vibeusa - Mon Oct 20 19:27:59 2008
Q. I'm having a hard time with this one, anyone care to explain? Tertiary alcohols undergo either substitution or dehydration depending on the reaction conditions. What is the mechanism of the reaction when 2-methyl-2-butanol is heated with concentrated sulfuric acid? Thanks!
Asked by Chance - Mon Oct 20 19:00:58 2008 - Chemistry - 1 Answers - 2 Comments
A. 2-methyl-2-butene. This will undergo an E1 reaction (elimination under acidic conditions) or for your sake, dehydration. The hydroxy oxygen will be protonated which results in a positive charge and thus forming a good leaving group. Then the cation dissociates, resulting a tertiary carbocation and water (this particular carbocation is the driving force of the reaction since it is stable and there's no positive charge on oxygen since oxygen is electronegative). Then the water molecule deprotonates the carbocation by taking a hydrogen from the beta carbon (the carbon adjacent to the positively charged carbon) resulting in 2-methylbutene.
Answered by vibeusa - Mon Oct 20 19:27:59 2008
What is the Chemical Equation for Combustion of Butanol used in Fuel?
Q. I need to know for my Chemistry Assigment. We are trying to find an Alternative for Fossil Fuels. And I chose Butanol. Answer the question above please
Asked by Mangobombz96 - Mon Mar 7 03:08:12 2011 - Chemistry - 2 Answers - Comments
Q. I need to know for my Chemistry Assigment. We are trying to find an Alternative for Fossil Fuels. And I chose Butanol. Answer the question above please
Asked by Mangobombz96 - Mon Mar 7 03:08:12 2011 - Chemistry - 2 Answers - Comments
What is the Kf of butanol and how many grams of water are present?
Q. The freezing point of butanol is 25.5 C. If 18.0 g of water are dissolved in 500 g of butanol, the solution freezes at 7.3 C. a) What is the Kf of butanol? b) If a 100 g butanol solution freezes at 23.59 C, how many grams of water are present?
Asked by Liliana - Sat Mar 21 16:19:21 2009 - Chemistry - 1 Answers - Comments
A. (a) Freezing point depression of dilute, ideal mixtures is given by: DTf = Kf i c Kf cryoscopic constant of the solvent i van't Hoff factor c molality of the solute (moles solute per kilogram solvent) Freezing point depression of that mixture is DTf = (25.5deg C - 7.3deg C) = 18.2deg C Because water don't dissociate in butanol, van't hoff factor is: i=1 The molality of water is c = (18.g / 18g/mol ) / 0.5kg = 2m Hence: Kf = DTf / i c = 18.2deg C / (1 2m) = 9.1deg C/m (or Kkg/mol) b) DTf = Kf i c => c = DTf / (Kf i ) = (25.5deg C - 23.59deg C) / (9.1deg C/m 1 ) = 0.21kg/mol => n(H2O) = c m(butanol) = = 0.21kg/mol 0.1kg = 0.021mol m(H2O) = n(H2O) M(H2O) = = 0.021mol 18g/mol = 0.378g
Answered by schmiso - Wed Mar 25 05:04:33 2009
Q. The freezing point of butanol is 25.5 C. If 18.0 g of water are dissolved in 500 g of butanol, the solution freezes at 7.3 C. a) What is the Kf of butanol? b) If a 100 g butanol solution freezes at 23.59 C, how many grams of water are present?
Asked by Liliana - Sat Mar 21 16:19:21 2009 - Chemistry - 1 Answers - Comments
A. (a) Freezing point depression of dilute, ideal mixtures is given by: DTf = Kf i c Kf cryoscopic constant of the solvent i van't Hoff factor c molality of the solute (moles solute per kilogram solvent) Freezing point depression of that mixture is DTf = (25.5deg C - 7.3deg C) = 18.2deg C Because water don't dissociate in butanol, van't hoff factor is: i=1 The molality of water is c = (18.g / 18g/mol ) / 0.5kg = 2m Hence: Kf = DTf / i c = 18.2deg C / (1 2m) = 9.1deg C/m (or Kkg/mol) b) DTf = Kf i c => c = DTf / (Kf i ) = (25.5deg C - 23.59deg C) / (9.1deg C/m 1 ) = 0.21kg/mol => n(H2O) = c m(butanol) = = 0.21kg/mol 0.1kg = 0.021mol m(H2O) = n(H2O) M(H2O) = = 0.021mol 18g/mol = 0.378g
Answered by schmiso - Wed Mar 25 05:04:33 2009
What is the stuctural formula of tert-butanol?
Q. If the molecular formula of ethanol is C2H6O and its structural formula is CH3CH2OH ... and if the molecular formula of isoprpanol is C3H8O and its structural formula is CH3CHOHCH3 ... what is the structural formula of tert-butanol whose molecular formula is C4H10O?
Asked by Justin G - Thu Nov 23 06:52:42 2006 - Chemistry - 3 Answers - Comments
A. Trick question, multiple answers. . . 1. CH3(CH2)3OH 2. C2H5CH(OH)CH3 3. (CH3)2CHCH2OH 4. (CH3)3COH 5. (C2H5)2O 6. CH3(CH2)2OCH3 7. (CH3)2CHOCH3 Ok, #4 is tert-butanol. All of these are structures for C4H10O go to and scroll down to the isomers section. All the diagrams are listed there.
Answered by akitashencp - Thu Nov 23 06:56:49 2006
Q. If the molecular formula of ethanol is C2H6O and its structural formula is CH3CH2OH ... and if the molecular formula of isoprpanol is C3H8O and its structural formula is CH3CHOHCH3 ... what is the structural formula of tert-butanol whose molecular formula is C4H10O?
Asked by Justin G - Thu Nov 23 06:52:42 2006 - Chemistry - 3 Answers - Comments
A. Trick question, multiple answers. . . 1. CH3(CH2)3OH 2. C2H5CH(OH)CH3 3. (CH3)2CHCH2OH 4. (CH3)3COH 5. (C2H5)2O 6. CH3(CH2)2OCH3 7. (CH3)2CHOCH3 Ok, #4 is tert-butanol. All of these are structures for C4H10O go to and scroll down to the isomers section. All the diagrams are listed there.
Answered by akitashencp - Thu Nov 23 06:56:49 2006
What is the freezing temperature of aspirin and t-butanol?
Q. I did a "freezing point depression" lab, and my book tells me that the accepted freezing temperature of butanol 25.6 degrees celcius, but it doesn't tell me the accepted freezing temp value of t-butanol (with aspirin dissolved in it). How can I find this answer?
Asked by Sunny_Smiles - Thu Feb 21 05:40:48 2008 - Chemistry - 2 Answers - Comments
A. This will depend on the concentration of aspirin that's dissolved in the solvent. The equation is delta T = ikm where T is temperature, i is van't Hoff number, k is the constant for the t-butanol (need to look it up) and m is the molality of aspirin (i.e. moles/kg of t-butanol). The i for aspirin, by the way, would be 1, unless it is the Na salt, and then it would be 2.
Answered by Simonizer1218 - Thu Feb 21 08:43:01 2008
Q. I did a "freezing point depression" lab, and my book tells me that the accepted freezing temperature of butanol 25.6 degrees celcius, but it doesn't tell me the accepted freezing temp value of t-butanol (with aspirin dissolved in it). How can I find this answer?
Asked by Sunny_Smiles - Thu Feb 21 05:40:48 2008 - Chemistry - 2 Answers - Comments
A. This will depend on the concentration of aspirin that's dissolved in the solvent. The equation is delta T = ikm where T is temperature, i is van't Hoff number, k is the constant for the t-butanol (need to look it up) and m is the molality of aspirin (i.e. moles/kg of t-butanol). The i for aspirin, by the way, would be 1, unless it is the Na salt, and then it would be 2.
Answered by Simonizer1218 - Thu Feb 21 08:43:01 2008
E1 dehydration of 2-butanol, what are the three alkenes obtained?
Q. When 2-butanol undergoes E1 dehydration of three alkenes are obtained. Which alkene would you predict to be formed in greatest abundance?
Asked by Jill - Thu Jul 17 09:22:14 2008 - Chemistry - 1 Answers - Comments
A. Since E1 means that intermediate cation is formed, the substituents have time to rearrange in energetically favourable way, so: trans 2 alkene will be formed maximally, followed by cis derivate and minimum of 1 alkene
Answered by Chloralhydrate - Thu Jul 17 10:04:02 2008
Q. When 2-butanol undergoes E1 dehydration of three alkenes are obtained. Which alkene would you predict to be formed in greatest abundance?
Asked by Jill - Thu Jul 17 09:22:14 2008 - Chemistry - 1 Answers - Comments
A. Since E1 means that intermediate cation is formed, the substituents have time to rearrange in energetically favourable way, so: trans 2 alkene will be formed maximally, followed by cis derivate and minimum of 1 alkene
Answered by Chloralhydrate - Thu Jul 17 10:04:02 2008
What Homologous series(family) does 1-butanol to which compound it belongs to ?
Q. Homologous series(family) to which the compound belongs) 1 - butanol Please help and explain while reasoning your answer
Asked by Nation D - Tue Jan 6 21:40:38 2009 - Chemistry - 1 Answers - Comments
A. butanol is an alcohol, so the series could include: methanol ethanol propanol butanol pentanol hexanol etc.
Answered by Nya - Thu Jan 8 00:58:03 2009
Q. Homologous series(family) to which the compound belongs) 1 - butanol Please help and explain while reasoning your answer
Asked by Nation D - Tue Jan 6 21:40:38 2009 - Chemistry - 1 Answers - Comments
A. butanol is an alcohol, so the series could include: methanol ethanol propanol butanol pentanol hexanol etc.
Answered by Nya - Thu Jan 8 00:58:03 2009
Results of a reaction between 1- butanol and potassium permanagate?
Q. What would happen in terms of colour of the solution, and any visible changes, or effects? Would a percipitate be formed at all?
Asked by Lorraine R - Tue Sep 28 18:28:01 2010 - Chemistry - 1 Answers - Comments
A. The purple colour of the pemanganate ion would be lost as it oxidised the alcohol and beame reduced to a brown precipitate of manganese dioxide or maybe eventually a virtually colourless solution of manganese(II) ions.
Answered by Chris S - Tue Sep 28 18:35:59 2010
Q. What would happen in terms of colour of the solution, and any visible changes, or effects? Would a percipitate be formed at all?
Asked by Lorraine R - Tue Sep 28 18:28:01 2010 - Chemistry - 1 Answers - Comments
A. The purple colour of the pemanganate ion would be lost as it oxidised the alcohol and beame reduced to a brown precipitate of manganese dioxide or maybe eventually a virtually colourless solution of manganese(II) ions.
Answered by Chris S - Tue Sep 28 18:35:59 2010
It si possible to find the absorption spectrum in NIR region for t-butanol?
Q. I found the IR spectrum but nothing in other regions with combinations of overtones.
Asked by cmg - Tue Jul 22 03:45:19 2008 - Chemistry - 4 Answers - Comments
A. You ll find it in this paper: Overtone spectroscopy of butanol S.B. Rai, P.K. Srivastava :Spectrochimica Acta Part A 55 (1999) 2793 2800 doi:10.1016/S1386-1425(99)00089-X
Answered by CJay - Tue Jul 22 12:26:34 2008
Q. I found the IR spectrum but nothing in other regions with combinations of overtones.
Asked by cmg - Tue Jul 22 03:45:19 2008 - Chemistry - 4 Answers - Comments
A. You ll find it in this paper: Overtone spectroscopy of butanol S.B. Rai, P.K. Srivastava :Spectrochimica Acta Part A 55 (1999) 2793 2800 doi:10.1016/S1386-1425(99)00089-X
Answered by CJay - Tue Jul 22 12:26:34 2008
Why does 1-butanol has a higher boiling point than diethyl ether?
Q. Why does 1-butanol has a higher boiling point than diethyl ether? Which compound would you expect to be more soluble in water? Why?
Asked by dabombdiggity58 - Mon May 19 02:03:41 2008 - Chemistry - 1 Answers - Comments
A. 1-butanol OH | C-C-C-C diethyl ether CH3-CH2-O-CH2-CH3 a) * I (think) the answer to this lies in the hydrogen bonds from the OH group to other OH groups. it has been a while since I've had Organic Chem. b) butanol. c) the terminal OH group makes the ends more polar and more soluable in water
Answered by Mike P - Mon May 19 02:26:09 2008
Q. Why does 1-butanol has a higher boiling point than diethyl ether? Which compound would you expect to be more soluble in water? Why?
Asked by dabombdiggity58 - Mon May 19 02:03:41 2008 - Chemistry - 1 Answers - Comments
A. 1-butanol OH | C-C-C-C diethyl ether CH3-CH2-O-CH2-CH3 a) * I (think) the answer to this lies in the hydrogen bonds from the OH group to other OH groups. it has been a while since I've had Organic Chem. b) butanol. c) the terminal OH group makes the ends more polar and more soluable in water
Answered by Mike P - Mon May 19 02:26:09 2008
What is the detailed mechanism for the formation of t-amyl hydrogen sulfate from 2-methyl-2-butanol?
Q. What is the detailed mechanism for the formation of t-amyl hydrogen sulfate from 2-methyl-2-butanol? I know the mechanism is Sn1.
Asked by DJ1203 - Sun Aug 2 19:30:04 2009 - Chemistry - 1 Answers - Comments
A. Sn1 means that something departs from the molecue first, typically leaving behind a carbocation, then something else add onto it (as opposed to Sn2, which is a concerted mechanism with a trigonal bipyramidal intermediate). Sn1 is more common for tertiary carbons (like your 2-methyl-2-butanol). Applied to your problem: Oxygen of alcohol donates electron pair to proton of sulfuric acid. Alcohol splits into a water molecule and a t-amylium carbocation. Carbocation receives electron pair from hydrogen sulfate ion to form end product. This reaction can be performed in reality using cold sulfuric acid as a reagent.
Answered by Xanthine - Sun Aug 2 19:45:11 2009
Q. What is the detailed mechanism for the formation of t-amyl hydrogen sulfate from 2-methyl-2-butanol? I know the mechanism is Sn1.
Asked by DJ1203 - Sun Aug 2 19:30:04 2009 - Chemistry - 1 Answers - Comments
A. Sn1 means that something departs from the molecue first, typically leaving behind a carbocation, then something else add onto it (as opposed to Sn2, which is a concerted mechanism with a trigonal bipyramidal intermediate). Sn1 is more common for tertiary carbons (like your 2-methyl-2-butanol). Applied to your problem: Oxygen of alcohol donates electron pair to proton of sulfuric acid. Alcohol splits into a water molecule and a t-amylium carbocation. Carbocation receives electron pair from hydrogen sulfate ion to form end product. This reaction can be performed in reality using cold sulfuric acid as a reagent.
Answered by Xanthine - Sun Aug 2 19:45:11 2009
How exactly do you write Butanol burned in oxygen?
Q. C4H9OH burned in oxygen Greg can I get your email so I can contact you for more help later on?
Asked by mmk - Mon Feb 23 00:37:21 2009 - Chemistry - 1 Answers - Comments
A. 2C4H9OH + 13O2 --> 8CO2 + 10H2O
Answered by grey's :] - Mon Feb 23 00:41:53 2009
Q. C4H9OH burned in oxygen Greg can I get your email so I can contact you for more help later on?
Asked by mmk - Mon Feb 23 00:37:21 2009 - Chemistry - 1 Answers - Comments
A. 2C4H9OH + 13O2 --> 8CO2 + 10H2O
Answered by grey's :] - Mon Feb 23 00:41:53 2009
From Yahoo Answer Search: 'butanol'
Fri Jan 20 04:26:54 2012